令f(x)=x^3-6x^2+4x+8,则：f(3)=-7.f'(x)=3x^2-12x+4,所以：f'(3)=-5f''(x)=6x-12,所以：f''(3)=6f'''(x)=6.,所以：f'''(3)=6.所以：f(x)=f(3)+f'(3)(x-3)+f''(3)/2(x-3)^2+f'''(3)/6(x-3)^3.=-7-5(x-3)+3(x-3)^2+(x...