设△ACE和△ECD的高为h,△ACB和△ACD的高为h1,∵S△ACE=1/2×AE×h,S△DCE=1/2×AE×h,又∵E是AD的中点,∴S△ACE=S△DCE,∵SABCE/S△AED=10/7,又∵SABCE=S△ABC+S△ACE,∴S△ABC/S△ADC＝3/14,又∵S△ABC=1/2×AB×h...