1/2(1-x)=1+m
两边乘以2,得
1-x=2+2m
-x-1=2m
x=-2m-1
3/4(x-1)-2/5(3x+2)=m/10-3(x-1)/2
两边乘以20,得
15(x-1)-8(3x+2)=2m-30(x-1)
15x-15-24x-16=2m-30x+30
-9x-31-2m+30x-30=0
21x-61=2m
x=(2m+61)/21
解互为相反数
则-2m-1+(2m+61)/21=0
-42m-21+2m+61=0
-40m+40=0
m=1