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3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27用加减消元法算的过程
人气:209 ℃ 时间:2020-06-10 09:51:29
解答
3(X-3)+10(2/3+Y)=13, ①22(X-3)+5(2/3+Y)=27②①-②×23(x-3)+10(2/3+y)-44(x-3)-10(2/3+y)=13-54-41(x-3)=-41x-3=1x=43×4+10(2/3+y)=1310(2/3+y)=12/3+y=1/10y=-17/30∴x=4,y=-17/30
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