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高中数学+化简(2cos10°-sin20°)/sin70°
人气:344 ℃ 时间:2020-06-19 16:58:09
解答
(2cos10°-sin20°)/sin70°
=(2cos10°-sin20°)/cos20°
=[cos10°+(cos10°-cos70°)]/cos20°
=[cos10°+2sin40°*sin30°]/cos20°
=[cos10°+2*1/2*sin40°]/cos20°
=[cos10°+cos50°]/cos20 °
=2cos30°*cos20°/cos20°
=2cos30°
=√ 3
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