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(通分) a/a^a^a+3a+2 ,a/a^a+2a+1 ,-1/3a+6
人气:496 ℃ 时间:2020-05-22 23:09:28
解答
a/(a^2+3a+2)=a/(a+1)(a+2)=a(a+1)/(a+1)^2(a+2)
a/(a^2+2a+1)=a/(a+1)^2=a(a+2)/(a+1)^2(a+2)
-1/(3a+6)=-1/3(a+2) =-1/3×(a+1)^2/(a+1)^2(a+2)
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