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证明tan^2x-sin^2x=tan^2 sin^2x
人气:273 ℃ 时间:2020-02-04 08:37:20
解答
tan^2x-sin^2x=sin^2x/cos^2x-sin^2x=
(1/cos^2x-1)sin^2x=[(1-cos^2x)/cos^2x]sin^2x=
[sin^2x/cos^2x]sin^2x=tan^2xsin^2x
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