令a=(2x-3)/(x^2-1)则(3x^2-3)/(2x-3)=3/a所以a-3/a-2=0a^2-2a-3=0(a+1)(a-3)=0a=-1,a=3(2x-3)/(x^2-1)=-12x-3=-x^2+1x^2+x-4=0x=(-1±√17)/2(2x-3)/(x^2-1)=32x-3=3x^2-33x^2-2x=x(3x-2)=0x=0,x=2/3所以x=(-1-√17...