设x=2001,原式变为：√[(x-1)*x*(x+1)*(x+2)+1-(x-1)^2]=√[x(x^2-1)(x+2)+1-(x-1)^2]=√[x^4+2x^3-x^2-2x+1-x^2+2x-1]=√[x^4+2x^3-2x^2]=x√[(x+1)^2-3]=2001√(2002^2-3)=2001√4008001 由于4008001为质数,故原式...