令t=3+2x-x²,0＜t≤4,∴-1＜x＜3则y=log/1/2 ty=log/1/2 t在R上单调递减,t=3+2x-x²在（-1,1）上单调递增,所以y=log/1/2 （3+2x-x²）在（-1,1）上单调递减y=log/1/2 t在R上单调递减,t=3+2x-x²在...