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用数学归纳法、证明不等式
1/(n+1)+1/(n+2)+1/(n+3)+…+1/3n>5/6 (n≥2)
人气:377 ℃ 时间:2020-01-29 08:51:48
解答
1.)当n=2时原式=1/3+1/4+1/5+1/6=57/60 >5/62.)假设当n=k时,(k为任意大于2的数)存在1/(k+1)+1/(k+2)+1/(k+3)+…+1/3k >5/63.)所以,当n=k+1时原式=1/(k+2)+1/(k+3)+1/(k+4)+…+1/3k+1/(3k+1)+1/(3k+2)+1/(3k+3)...
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