sin(A+B)=1/2,sin(A-B)=1/3,sinAcosB+cosAcosB=1/2 (1)sinAcosB-cosAcosB=1/3 (2)(1)+(2):2sinAcosB=5/6(1)-(2):2cosAsinB=1/6【tan(A+B)-tanA-tanB]/[tanB*tanB*tan(A+B)]=[(tanA+tanB)/(1-tanAtanB)-tanA-tanB]/[t...