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倒数相加
√(x-y)/2-2/√(x-y)
人气:400 ℃ 时间:2020-05-29 05:37:58
解答
√(x-y)/2-2/√(x-y)
=(x-y)/vx-y-2/vx-y
=(x-y-2)/v(x-y)
=(x-y-2)vx-y/(x-y)
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