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x+4/3=y+3/2=z+8/4,且x+y+z=12,求x,y,z的值?
人气:284 ℃ 时间:2020-06-27 15:28:19
解答
x+4/3=y+3/2,得到x=y+1/6;
y+3/2=z+8/4,得到z=y-1/2;
将上两式代入x+y+z=12;得到:
y+1/6+y+y-1/2=12; 解得y=37/9;
x=y+1/6=213/54;
z=y-1/2=65/18;
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