证明 (2sinα-sin2α)/(2sinα+sin2α)=tan²(θ/2)
tan(π/4+α)-cot(π/4+α)=2tan2α
人气:311 ℃ 时间:2020-04-15 02:45:59
解答
证明:左边=(2sinα-2sinαcosα)/(2sinα+2sinαcosα)=(1-cosα)/(1+cosα)
=2sin²(α/2)/2cos²(α/2)=tan²(α/2)=右边(那个是α吧)可以帮我回答一下tan(π/4+α)-cot(π/4+α)=2tan2α证明:tan(π/4-α)=cot(π/4+α)左边=(1+tanα)/(1-tanα)-(1-tanα)/(1+tanα)=4tanα/(1-tan²α)(通分)右边=4tanα/(1-tan²α)=左边∴tan(π/4+α)-cot(π/4+α)=2tan2α
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