根据题意：df(1／x²)／dx＝(f(1／x²))'＝f'(1／x²)·(1／x²)'＝f'(1／x²)·(﹣2／x³)＝1/x∴f'(1／x²)＝﹣x²／2令 x²＝2得f'(1／2)＝﹣1[f(x＋Δx)－f(x)]／Δx＝f'(x...