f(x,y)=3xy-x^3-y^3
由f'x=3y-3x^2=0,得y=x^2
由f'y=3x-3y^2=0,得x-(x^2)^2=0,得x(1-x^3)=0,得x=0或1,故y=0或1
A=f"xx=-6x
B=f"xy=3
C=f"yy=-6y
当x=0,y=0时,A=C=0,B=3,AC-B^2=-9