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已知函数f(x)=cos(2x-π/3)+sin^2x-cos^2x,设函数g(x)=[f(x)]^2+f(x),求g(x)值域
人气:118 ℃ 时间:2019-10-08 20:44:14
解答
∵f(x)=cos(2x-π/3)+(sinx)^2-(cosx)^2=cos(2x-π/3)-cos2x=2sin(2x-π/6)sin(π/6)=sin(2x-π/6).∴g(x)=[sin(2x-π/6)]^2+sin(2x-π/6)=[sin(2x-π/6)+1/2]^2-1/...
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