求满足下列条件的所有正整数解3x+2y-z=4,2x-y+2z=6,x+y+z＜7_数学解答

求满足下列条件的所有正整数解3x+2y-z=4,2x-y+2z=6,x+y+z＜7

人气：466 ℃　时间：2020-03-29 11:09:00

解答

3x+2y-z=4 (1)
2x-y+2z=6 (2)
(1)×2+(2)
8x+3y=14
y=(14-8x)/3>0
14-8x>0
x0
16-7x>0
x