(lg2)^2+lg5lg20-1_数学解答

(lg2)^2+lg5lg20-1

人气：394 ℃　时间：2020-04-02 18:54:16

解答

=(lg2)^2+lg5(lg5+lg4)-1
=(lg2)^2+(lg5)^2+2*lg5*lg2-1
=(lg2+lg5)^2-1
=1-1
=0

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