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已知x/y=3,求x²+2xy-3y²/x²-xy+y²
人气:332 ℃ 时间:2019-10-29 10:52:34
解答
x²+2xy-3y²/x²-xy+y²
=(x/y)²+2x/y-3/((x/y)²-x/y+1)
=(9+6-3)/(9-3+1)
=12/7不明白x²+2xy-3y²/x²-xy+y² (分子分母同时除以y²) =【(x/y)²+2x/y-3】/((x/y)²-x/y+1) =(9+6-3)/(9-3+1) =12/7
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