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f(x)=sin(x+7π\4)+cos(x-3π\4) 求fx的最小正周期
人气:409 ℃ 时间:2020-06-26 13:35:42
解答
f(x)=sin(x+7π\4)+cos(x-3π\4)
=sinxcos7π/4+cosxsin7π/4+cosxcos3π/4+sinxsin3π/4
=sinxcosπ/4-cosxsinπ/4-cosxcosπ/4+sinxsinπ/4
=根号2/2sinx-根号2/2cosx-根号2/2cosx+根号2/2sinx
=根号2sinx-根号2cosx
=2(根号2/2sinx-根号2/2cosx)
=2sin(x-π/4)
T=2π/1=2π
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