由4^n=2可得n=1/2,所以2^2m-4n+1 =(2^m)(2^m)-4n+1=3X3-4X1/2+1=8如果是题目表达不明确,(2m-4n+1) 整个都是指数,则：2^(2m-4n+1) = (2^2m) / 2^4n X 2 = 2(2^m)(2^m) / (((2^2)^n)^2) = 2X3X3/((4^n)^2) = 18/4 =4.5...