(2+1)(2^2+1)(2^4+1)(2^8+1)如何用平方差公式解?
人气：378 ℃ 时间：2020-06-14 19:32:14
解答
(2+1)(2^2+1)(2^4+1)(2^8+1)……（2^64+1)+1 =1*(2+1)(2^2+1)(2^4+1)(2^8+1)=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)=(2^2-1)(2^2+1)(2^4+1)(2^8+1) =(2^4-1)(2^4+1)(2^8+1)=(2^8-1)(2^8+1)=2^16-1
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