6/(x-1)=(x+k)/「x(x-1)」-3/x 6x
=(x+k)-3(x-1) 6x
=-2x+(k+3) k
=8x-3
因为x≠0,x≠1
当x=0时,k=8*0-3=-3
当x=1时,k=8*1-3=5
所以,k≠-3,k≠5
即:k≠-3且k≠5时分式方程6/(x-1)=(x+k)/「x(x-1)」-3/x都有解:(k+3)/8