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(x+1)(x²+1)(x⁴+1)(x^8+1)(x-1)
人气:426 ℃ 时间:2020-09-29 22:59:12
解答
(x+1)(x²+1)(x⁴+1)(x^8+1)(x-1)
=(x+1)(x-1)(x²+1)(x⁴+1)(x^8+1)
连续平方差
=(x²-1)(x²+1)(x⁴+1)(x^8+1)
=(x^4-1)(x⁴+1)(x^8+1)
=(x^8-1)(x^8+1)
=x^16-1
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