x^log2(x+2)=8 解对数方程.
RT
人气:325 ℃ 时间:2020-03-26 06:53:53
解答
e^x^log2(x+2)=e^8 -> log2(x+2)=e^8 -> log2+log(x+2)=e^8
-> log(x+2)=e^8-log2
等式右面是一个常数,设它为m,则x+2=e^m
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