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a-1-(a²/a-1)
(4/a+2)+a-2
(1/x-3)-(1/x+3)
人气:131 ℃ 时间:2020-06-14 13:28:48
解答
1、原式=((a-1)(a-1))/(a-1)-a^2/(a-1)=(a^2-2a+1-a^2)/(a-1)=(1-2a)/(a-1)2、原式=4/(a+2)+((a+2)(a-2))/(a+2)=(4+(a+2)(a-2))/(a+2)=(4+a^2-2^2)/(a+2)=a^2/(a+2)3、原式=(x+3)/((x-3)(x+3))-(x-3)/((x-3)...
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