64^(n+1)÷32^n÷16^(n-1)×2^(3n-4)
=(2^6)^(n+1)÷(2^5)^n÷(2^4)^(n-1)×2^(3n-4)
=2^[6(n+1)-5n-4(n-1)+(3n-4)]
=2^(6n+6-5n-4n+4+3n-4)
=2^6
=64