f(x) = cos^2x+√3sinx*cosx= (cos2x+1)/2 + √3/2sin2x= √3/2sin2x + 1/2cos2x +1/2= sin(2x+π/6) + 1/2所以当2x+π/6= 2kπ+π/2 即x=kπ+π/6时f(x)取得最大值为 3/2当2x+π/6= 2kπ-π/2 即x=kπ-π/3时f(x)取...