x³+y³
=(x+y)(x²-xy+y²)
=(x+y)[(x+y)²-3xy]
=1×[1²-3×(-1)]
=1×(1+3)
=1×4
=4
x^4+y^4
=(x^4+y^4+2x²y²)－2x²y²
=(x²+y²)²－2x²y²
=[(x+y)²－2xy]²－2x²y²
=[1²－2×(-1)]²－2×(-1)²
=(1+2)²-2×1
=3²-2
=9-2
=7