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数学
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化简sin2a(1+tana*tana/2)
人气:161 ℃ 时间:2020-05-16 18:31:29
解答
sin2a(1+tana*tana/2)
=2sinacosa[1+(sina/cosa)*(sina/2/cosa/2)]
=2sinacosa+2(sina)^2*[(sina/2)^2/(sina/2*cosa/2)]
=2sinacosa+2(sina)^2[(1-cosa)/sina)]
=2sinacosa+2sina(1-cosa)
=2sina.
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