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1/1*2+1/2*3+1/3*4+……+1/n(n+1)=?
人气:335 ℃ 时间:2020-04-15 05:56:20
解答
1/1*2+1/2*3+1/3*4+...+1/n(n+1)
=(1/1)-(1/2)+(1/2)-(1/3)+(1/3)-(1/4)+...+(1/n)-1/(n+1)
=1-1/(n+1)
=(n+1-1)/(n+1)
=n/(n+1)
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