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化简sin(A+π/4)sin(A-π/4)/sin^4A-cos^4A
人气:114 ℃ 时间:2020-06-20 15:09:58
解答
原式=cos[π/2-(A+π/4)]sin(A-π/4)/(sin²A+cos²A)(sin²A-cos²A)
=cos(π/4-A)sin(A-π/4)/1×(sin²A-cos²A)
=cos(A-π/4)sin(A-π/4)/1×(sin²A-cos²A)
=[1/2sin2(A-π/4)]/cos2A
=[1/2sin(2A-π/2)]/cos2A
=[-1/2cos2A]/cos2A
=-1/2
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