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一道计算题,求高手帮忙!1/2+1/4+1/8+1/16+1/128+1/256+…+1/2^n
计算:1/2+1/4+1/8+1/16+1/128+1/256+…+1/2^n
急!
人气:234 ℃ 时间:2020-05-09 20:45:13
解答
x=1/2+1/4+1/8+1/16+1/128+1/256+…+1/2^n
2x=1+1/2+1/4+1/8+1/16+1/128+1/256+…+1/2^n-1
两式相减,x=1-1/2^n
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