sin25π/6+cos10π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)=
人气:147 ℃ 时间:2020-06-22 14:23:29
解答
sin25π/6+cos10π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)=sin(4π+ π/6)+cos(4π - 2π/3)+tan(-6π- π/4)+sin(-2π - π/3)×cos(-2π - π/6)=sin(π/6)+cos(2π/3) + tan(-π/4) + sin(- π/3)×cos(- ...
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