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计算:sin25π/6+cos25π/4+tan(-25π/4)+sin(-26π/3)
人气:340 ℃ 时间:2020-07-02 18:10:54
解答
原式=sin(4π+π/6)+cos(6π+π/4)-tan(6π+π/4)-sin(8π+2π/3)
=sinπ/6+cosπ/4-tanπ/4-sin2π/3
=1/2+√2/2-1-√3/2
=(√2-√3-1)/2
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