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1/ln(x+1)-1/sinx 当x趋向于0时的极限
人气:135 ℃ 时间:2020-03-27 23:23:32
解答
lim1/ln(x+1)-1/sinx
=lim [sinx-ln(x+1)]/sinx*ln(x+1)
=lim[sinx-ln(x+1)]/x*x
=lim(cosx-(1/x+1))/2x
=lim(-sinx+1/(x+1)^2)/2
=1/2
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