已知抛物线y=x^2+mx+2m-m^2,根据以下条件,分别求出相应的m值1）抛物线的最小值为-1y=x^2+mx+2m-m^2=x^2+mx+m^2/4-m^2/4+2m-m^2=(x+m/2)^2-5m^2/4+2m-5m^2/4+2m=-15m^2-8m-4=0(5m+2)(m-2)=0m=-2/5 m=22）抛物线与x轴...