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数学
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((√(XY+1))-1)÷XY求在(X,Y)在(0,0)的极限
求详解,书上写的看不懂
人气:306 ℃ 时间:2020-05-04 18:37:20
解答
分子有理化,该式化为:
(xy+1-1)/[xy(√(xy+1)+1)]
=xy/[xy(√(xy+1)+1)]
=1/(√(xy+1)+1)
则当x--->0,y--->0时,上式极限为1/2
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