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计算.(1)(x的三次方+x²+x+1)/(x+1) (2)(ab²-a²b)/(a-b)
人气:486 ℃ 时间:2019-09-27 16:23:15
解答
(1)(x的三次方+x²+x+1)/(x+1) =[﹙x³+x²﹚+(x+1)]/(x+1)= [x²﹙x+1﹚+﹙x+1﹚]/﹙x+1﹚=﹙x+1﹚﹙x²+1﹚/﹙x+1﹚=x²+1(2)(ab²-a²b)/(a-b)=ab﹙b-a﹚/﹙a-b﹚=...
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