lim(x→+∞)(x+sinx)/(√(x^2+1)) 根据罗比达法则lim(x→+∞)(x+sinx)/(√(x^2+1)) =lim(x→+∞)(1+cosx)/(x/√(x²+1))∵lim(x→+∞)(x/√(x²+1))=1而lim(x→+∞)(1+cosx)极限不存在∴lim(x→+∞)(x+sinx)...