x^2+y^2+xy-3y+3=0x^2+xy+y^2/4+3y^2/4-3y+3=0x^2+2*x*(y/2)+(y/2)^2+(√3y/2)^2-2*(√3y/2)*(√3)+(√3)^2=0(x+y/2)^2+(√3y/2-√3)^2=0所以x+y/2=0,√3y/2-√3=0所以x=-1,y=2所以xy=-2如果不懂,祝学习愉快!...好，谢了