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等比数列an是递增的等比数列,且满足a1a4=27,a2+a3=12 求通项公式an
人气:354 ℃ 时间:2020-04-08 04:17:32
解答
设公比为n,则a2=a1×n,a3=a1×n^2,a4=a1×n^3原式a1a4=27即为a1^2×n^3=27; ①a2+a3=12 即为a1×n+a1×n^2=12 ②由①可知a1=(27/n^3)^0.5 ,将a1=(27/n^3)^0.5带入等式②(等式两边开平方)可得如下等式:27n^2-90n+2...
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