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sin(4π/3)*cos(25π/6)*tan(-3π/4)
人气:123 ℃ 时间:2020-06-17 04:20:16
解答

sin(4π/3)cos(25π/6)tan(-3π/4)
=sin(π+π/3)cos(4π+π/6)tan(π/4-π)
=sinπ/3cosπ/6tanπ/4
=√3/2×√3/2×1
=3/4
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