> 数学 >
已知直角坐标系中,点P(x,y)满足
x2−4
+(y+3)2=0,则点P坐标为(  )
A. (2,-3)
B. (-2,3)
C. (2,3)
D. (2,-3)或(-2,-3)
人气:218 ℃ 时间:2020-06-30 05:20:06
解答
x2−4
+(y+3)2=0,
x2−4=0
y+3=0

解得
x=2
y=−3
x=−2
y=−3

∴点P坐标为(2,-3)或(-2,-3).
故选:D.
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版