方程x^3-5*x^2+8*x-4=0化简_数学解答

方程x^3-5*x^2+8*x-4=0化简

人气：448 ℃　时间：2020-03-25 01:34:42

解答

x³ - 5x² + 8x - 4 = 0( x³ - x² ) - (4x² - 4x) + (4x - 4) = 0x²(x-1) - 4x(x-1) +4(x-1) = 0(x-1)(x² - 4x+4) = 0(x-1)(x - 2)² = 0x=1 或 x=2