由x²+x-6=0解得x1=2,x2=-3,（x+1-3/（x-1）)÷（x平方-4x+4）/（x-1）=(X-2)(X+2)/[(x+1)(x-1)]*(x-1)/(x-2)²=(X+2)/[(X+1)(X-2)]当X=2时,原式无意义；当X=-3时,原式=(-3+2)/[(-3+1)(-3-2)]=-1/10...