1.已知函数y=f(x),x∈[a,b],那么集合{(x,y)|y=f(x),x∈[a,b]}∩{(x,y)|x=2}中元素的个数为.
2.已知定义在R上的奇函数f(x)满足f(x+2)=-f(x),则f(6)=
3.奇函数f(x)在(-无穷大,0)上单调递减,f(2)=0,不等式(x-1)f(x-1)>0的解集是.
4.已知函数y=f(x)是定义在R上的偶函数,当x<0时,f(x)是单调递增的,则不等式f(x+1)>f(1-2x)的解集是.
5.若f(x)为R上的奇函数,且在(0,+无穷大)内是增函数,又f(-3)=0则(x-1)f(x)<0的解集为.
6.设f(x)是(负无穷大,正无穷大)上的奇函数,f(x+2)=-f(x),0≤x≤1时,f(x)=x,则f(7.5)=.
7.定义在(0,正无穷大)上的函数y=f(x)满足f(xy)=f(x)+f(y),f(1/3)=1,且x>1时,f(x)<0
(1)证明y=f(x)为(0,正无穷大)上的单调减函数
(2)如果f(x)+f(2/3-x)≤2,求x的值
人气:378 ℃ 时间:2020-01-24 21:41:38
解答
1.如果2不在区间[a,b]之间,那么个数是0,如果2在区间[a,b]之间,那么个数是1.2.由于是奇函数,就有f(0)=0,f(6)=-f(4)=f(2)=-f(0)=0.3.f(x)是奇函数,关于原点对称,所以f(x)=-f(-x),所以f(-2)=-f(2)=0....第6我做出来-0.5。。。有几个区间我很你不一样。。第6个是0.5
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