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分解因式:x(x-y)(x²-xy-y²)-x²y(y-x)
人气:278 ℃ 时间:2020-02-04 00:54:40
解答
x(x-y)(x²-xy-y²)-x²y(y-x)
=x(x-y)(x²-xy-y²)+x²y(x-y)
=x(x-y)(x²-xy-y²+xy)
=x(x-y)(x²-y²)
=x(x-y)²(x+y)=x(x-y)(x²-xy-y²)+x²y(x-y)=x(x-y)(x²-xy-y²+xy)是怎么得到的?提取公因式x(x-y)前面余下因式 x²-xy-y²后面余下xy
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